50t=4t^2=100

Solution for 50t=4t^2=100 equation:

50t=4t^2=100

We move all terms to the left:

50t-(4t^2)=0

determiningTheFunctionDomain
-4t^2+50t=0

a = -4; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·(-4)·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*-4}=\frac{-100}{-8}
=12+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*-4}=\frac{0}{-8}
=0
$